
Samira Vishwas
Tezzbuzz|18-06-2026
Delhi: Team India has maintained its winning streak in the Women’s T20 World Cup 2026. The team led by Harmanpreet Kaur defeated Netherlands by 95 runs in the tenth match of the tournament on Wednesday and scored 2 points. With the help of this big win, Team India has reached the top in Group A.
In this match held in Leeds, the Indian team batted first after losing the toss and with the help of half-centuries from Smriti Mandhana (74) and Shefali Verma (55), scored 209/5 after playing the entire over.
Team India made a total of more than 200 for the first time in the history of T20 World Cup. Team India managed to score more than 200 for the fifth time in T20I. Caroline de Lange took maximum 2 wickets in the Indian innings.In the counter innings, a shameful performance was seen from the players of Netherlands. Only 4 players of the team were able to cross the double figures.
Wicketkeeper batsman and captain Babette de Leede scored the maximum 28 runs for the team. Due to the dangerous bowling of Shri Charani, the Dutch team was all out for 114 runs in 17.3 overs. Shri Charani took maximum 4 wickets in his name.Smriti Mandhana – 74 Run
Shefali Verma – 55 Run
Caroline de Lange – 2 wickets taken
babette de leyde – 28 runs
India defeated Netherlands by 95 runs.
Smriti Mandhana
Answer: India won the match by 95 runs.
Answer: Smriti Mandhana Was chosen player of the match.
Answer: India:209/5
Netherlands:114
Answer: India:209/5
Netherlands:114




